If one zero of the quadratic polynomial 4x2-8kx-9 is negative of the other, Find the value of k
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Answered by
4
Answer:
0
Step-by-step explanation:
Let one zero be α
the other zero be -α
The sum of the roots =-b/a
α+(-α)=8k/4
0. =2k
k. =0
Hence the value of k is 0.
manishshetty276:
thx
Answered by
1
Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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