if one zero of the quadratic polynomial 4x2-8kx-9 is negative of the other find the value of k
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Answered by
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Let two roots of quadratic equation are x(1) & x(2).
Then according to question,
x(1) = -x(2)
x(1) + x(2) = 0
-(b/a)=0 ( sum of roots = -(coefficient of x / coefficient of x^2) )
8k/4=0
k=0
Thanks!
asukanna:
Nice
Answered by
1
Step-by-step explanation:
Answer :-
→ k = 0 .
Step-by-step explanation :-
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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