if one zero of the quadratic polynomial ax² + bx + c is cube of other, then the value of sum of the cubes of the zeros is?
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Answer is 3abc-b^3/a^3
Step by step solution:
Let p and q be the roots of the equation
Given p=q^3
We know that p+q = -b/a
pq= c/a
Now let us consider (p+q)^3=p^3+q^3+3pq(p+q)
(-b/a)^3=p^3+q^3+3(c/a)(-b/a)
-b^3/a^3=p^3+q^3-3bc/a^2
P^3+q^3=3bc/a^2-b^3/a^3
Taking lcm, we get a^3,
p^3+q^3=3abc-b^3/a^3
Hope it helped u a lot friends .
Praise Jesus for helping me in solving this and helping all of u
Thank jesus
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