If one zero of the quadratic polynomial f(x)=4^2-8kx-9 is negative of the other,find the value of k.
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Answered by
57
Given f(x) = 4x^2 - 8kx - 9.
It is in the form of ax^2 + bx + c = 0 Where a = 4, b = -8k.
The sum of roots = -b/a.
8k/4 = 0
2k = 0
k = 0.
Hope his helps!
It is in the form of ax^2 + bx + c = 0 Where a = 4, b = -8k.
The sum of roots = -b/a.
8k/4 = 0
2k = 0
k = 0.
Hope his helps!
8877715103:
Bhai
Answered by
42
hello users ....
solution:-
we know that;
for a quadratic equation
ax² + bx + c = 0
α + β = -b/a
where,
α,β are the roots of equation.
here,
According to given;
one root of equation is negative of other
=> α = -β
=> α + β = 0
here,
for quadratic equation...
4x² -8kx -9 = 0
α + β = -b/a = - (-8k/4)
=> 8k/4 = 0
=> 8k = 0
=> k = 0 Answer
⭐✡ hope it helps ⭐✡
solution:-
we know that;
for a quadratic equation
ax² + bx + c = 0
α + β = -b/a
where,
α,β are the roots of equation.
here,
According to given;
one root of equation is negative of other
=> α = -β
=> α + β = 0
here,
for quadratic equation...
4x² -8kx -9 = 0
α + β = -b/a = - (-8k/4)
=> 8k/4 = 0
=> 8k = 0
=> k = 0 Answer
⭐✡ hope it helps ⭐✡
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