If one zero of the quadratic polynomial f(x) equals to four x square minus 8kx- nine is negative of the other ,find the value of k
Answers
Answered by
9
Hey!
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Let @ (alpha) and ß (beta) be the zeroes of the quadratic polynomial 4x^2 - 8kx - 9
Given,
@ = - ß
Then,
@ + ß = 0
- b / a = 0
- (-8kx ) / 4 = 0
8kx / 4 = 0
2k = 0
k = 0
________________
Hope it helps...!!!
________________
Let @ (alpha) and ß (beta) be the zeroes of the quadratic polynomial 4x^2 - 8kx - 9
Given,
@ = - ß
Then,
@ + ß = 0
- b / a = 0
- (-8kx ) / 4 = 0
8kx / 4 = 0
2k = 0
k = 0
________________
Hope it helps...!!!
Answered by
6
Heya !
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Comparing f(x) = 4x2 - 8kx - 9 with ax2+bx+c we get
a=4;
b=-8k and
c=-9.
Since one root is the negative of the other, let us assume that the roots are p an -p.
Sum of the roots, a+(-a)=-b/a=-(-8k)/4
0=2k
k=0
____________
Hope it helps u !!!
Cheers :))
# Nikky
_____________
Comparing f(x) = 4x2 - 8kx - 9 with ax2+bx+c we get
a=4;
b=-8k and
c=-9.
Since one root is the negative of the other, let us assume that the roots are p an -p.
Sum of the roots, a+(-a)=-b/a=-(-8k)/4
0=2k
k=0
____________
Hope it helps u !!!
Cheers :))
# Nikky
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