If one zero of the quadratic polynomial (k + 3) x2 + kx + 3 is −2 find k
Answers
Answered by
1
HOL@ M@T€...!!!
Zero of p(x) is =-2
p(x) = (k+3)x²+kx+3
To Find :- value of k
putting value of x = -2 and putting p(x) = 0
(k+3)x²+kx+3=0
(k+3)×(-2)²+k(-2) +3 =0
(k+3)4-2k+3=0
(k+3)1-2k=0
k+3-2k=0
-2k+k=-3
-k=-3
k = 3
Hope it helps you...
Answered by
0
hey mate
given polynomial
(k+3)x²+k x + 3=0. .....(1)
if -2 is s zeroes of given polynomial
so,
x=-2 satisfies this polynomial
,
so
x= -2 , put in equation (1),we get
(k+3) (-2)² + k(-2)+3=0
4k +12 -2k +3=0
2k= -15
k= -15/2
thus :
value of k = -15/2
I hopes its help's u.
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@abhi.
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