Question

If one zero of the quadratic polynomial (x-1)x2+kx+1 is -3 find k

Answer 1

Answer:

${(x - 1)}^{2} + kx + 1 = 0 \: \: \: \:$

if x= -3 then

${( - 3 - 1)}^{2} + ( - 3)k + 1 = 0$

$16 - 3k + 1 = 0$

$- 3k = - 17$

$k = \frac{17}{3}$

Ans

Answer 2

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