If one zero ofpolynomial 3x^2-8x-2k-1 is seven times the other then the zeros are
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the factors are 1/3 and 7/3
Step-by-step explanation:
First ket the factors be xand7x
then put both the factors individually in the equation and coz they are the factors so the output will come out to be 0. So we can equate both of them. After equating them we will get the value of x as 1/3
So the 1st factor is x i.e. 1/3
and the second factor is 7x i.e. 7/3
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