PQ is a chord of circle and R is point on minor Arc if PT is tangent at point P such that angle QPT = 60 degree then find angle PRQ.
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hey here is your answer
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pls refer the reference diagram uploaded above
Step-by-step explanation:
so here pt is a tangent and pq is a chord
so here angle qpt is an angle inscribed between both of these
so by tangent chord theorem
we get
angle qpt=1/2×m(arc pq)
ie m(arc pq)=60×2
=120 degrees
so thus m(major arc pq)=360-m(minor arc pq)
=360-120
=240 degrees
thus then
here angle PRQ intercepts major arc pq on circumference of circle
thus by inscribed angle theorem
we get
angle PRQ=1/2×m(major arc pq)
=1/2×240
=120 degrees
thus angle PRQ is 120 degrees
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