Question

If one zeroes of polynomial (k-1) x2+kx+1 is -3then find the value of K.

Answer 1

Answer:

k=1

Explanation:

k-1=0

k=1

substitute k=1 in x^2+kx+1

x^2+1x+1=0

x^2+x+1

Answer 2

The value of k is :

• Given equation : (k-1)x^2 + kx + 1

• Also given that -3 is one the zeros of given quadratic equation.

•Putting x = -3 in equation,

(k-1)×(-3)^2 + k(-3) + 1 = 0

9(k-1) - 3k + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

• k = 8/6 = 4/3

• Hence, value of k is 4/3