Math, asked by manvimurthy6988, 11 months ago

The measure of side of a triangle are in proportion 2:3:4 and its perimeter is 180 cm then find its area

Answers

Answered by snehadhiman555
1

Step-by-step explanation:

let 2:3:4 = 2x,3x,4x

2x+3x+4x= 180

9x=180

x=180/9

x=20

2x= 2×x

= 2×20

=40

3x=3×20

=60

4x=4×20

=80

area of triangle= side×side

=40×60×80

=192000cm ANSWER

Answered by Samir0404
0

Step-by-step explanation:

let X be the common ratio

then measure of side of traingle are 2x,3x,and 4x

perimeter of traingle = 180cm

2x+3x+4x=180cm

9x=180

x=180/9

x=20

then sides are 2x= 2*20=40cm

3x= 3*20=60cm

4x= 4*20=80cm

semi perimeter= 90cm

area =√{s(s-a)(s-b)(s-c)}

=√{90(90-40)(90-60)(90-80)}

=√{90*50*30*10}

=√{1350000}

=√{90000*15}

=300√15 sq. cm

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