Question

If OP is perpendicular to AB,prove that AP=BP

Answer 1

Hey mate!

Here's your answer!!
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AB is the chord of the circle.
Join A and B to O.

In triangle APO and BPO,
AO = BO (radii of the same circle)

ΔAPO = ΔBPO (Given OP _|_ AB)
OP = OP (Common side)

Therefore, two triangles are congruent by SAS congruency.

AP = BP (cpct)
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Answer 2

$hey \: dear \: here \: is \: your \: answer$

In OPA and OPB.


AO = BO (radii of the same circle)

<APO = <BPO (since,OP ⊥ AB)

OP = OP (since,common side)

:. two triangles are congruent by SAS congruency

AP = BP ( by cpct)


☺ Hope this helps you deaR ✌✌