If origin is the centre of a circle with radius 17 units, find the coordinates of any four points on the circle which are not on the axes. (Use the Pythagorean triplets)
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the co-ordinates can be represented as (17cos(Ф),17sin(Ф))
where Ф ∈ [0,2π]
so for any four points
take Ф=30,45,60 and 75
so the co-ordinates are (17√3/2,17/2) (17/√2,17/√2) (17/2,17√3/2) and (4.4,16.42)
where Ф ∈ [0,2π]
so for any four points
take Ф=30,45,60 and 75
so the co-ordinates are (17√3/2,17/2) (17/√2,17/√2) (17/2,17√3/2) and (4.4,16.42)
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