Question

If P = (0, 1), Q = (0, -1) and R = (0, 2) then the locus of the point P such that SQ² + SR² = 2SP² is a

1)straight line parallel to x-axis

2) circle with centre (0,0)


3) circle through (0, 0)

4) straight line parallel to y-axis​

Answer 1

Answer:

Correct answer is

A straight line parallel to y axis.

Explanation

p(1,0) q(-1,0),r (2,0). s(x,y)

sq^2+sr^2=2sp^2

(x+1)^2+(y-0)^2(x-2)^2+(y-0)^2 = 2{(x-1)^2+(y-1)^2}

x^2+2x+1+y^2+x^2+4-4x+y^2= 2{x^2-2x+1+y^2}

= 2x^2-4x+2+2y^2

2x+3=0

x=-3/2

Answer is. A straight line parallel to y axis.

Hope it helps you my friend

Answer 2

Answer:

straight line parallel to y-axis​

Step-by-step explanation:

p(1,0) q(-1,0),r (2,0). s(x,y)

sq^2+sr^2=2sp^2

(x+1)^2+(y-0)^2(x-2)^2+(y-0)^2 = 2{(x-1)^2+(y-1)^2}

x^2+2x+1+y^2+x^2+4-4x+y^2= 2{x^2-2x+1+y^2}

= 2x^2-4x+2+2y^2

2x+3=0

x=-3/2