If
p
1,
3
is the mid-point of the line segment joining the points (2, 0) and
2
0,
9
,
then show that the line 5x + 3y + 2 = 0 passes through the point (–1, 3p)
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Midpoint of points P(2,0) and Q(0,29) is given by, (x1+x22,y1+y22)
Midpoint of P(2,0) and Q(0,29) = (22,292) = (1,19)
Given (1,p3) is the midpoint of points P(2,0) and Q(0,29)
So, p3 = 19p =13We have to show that ,Line 5x+3y+2=0..(1)
passes through the point (−1,3×13)
Substituting the values of x = −1 and y =1 in equ (i),
we get5(−1)+3(1)+2 = 0−5+3+2=0−5+5 = 0
LHS = RHS.
So, the given line 5x+3y+2=0 passes through the point (−1,1)
☆☆hope this helps☆☆
anshiketa1308:
thx
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