If p-1,p 3,3p-1 are in ap then fimd the value of p
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Answered by
5
If a,b,c are in AP ,then b-a = c-b
So , 2b = a+c
Here , a= p-1
b = 3
c=3p-1
So, 2*3 = p-1 + 3p-1
6 = 4p - 2
P=2
So , 2b = a+c
Here , a= p-1
b = 3
c=3p-1
So, 2*3 = p-1 + 3p-1
6 = 4p - 2
P=2
Answered by
3
Let suppose a, b, c are in Arithmetic Progression (AP) , then we know that,
b-a = c-b
So here we can say that, 2b = a+c --) 1
and now,
1. a= p-1
2. b = p+ 3
3. c=3p-1
So that put b=3, and point 1 and 3 in equation 1 and we will get,
--> 2*3 = p-1 + 3p-1
--> 6+2p = 4p - 2
8=2p
P=4
So that the value of P is 4
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