Question

If p – 1, p + 3, 3p – 1 are in AP, then find the value of p

Answer 1

For AP

nth term = a + (n-1)d

For given AP

a = p-1, d = (p+3 - p +1) =4

For 3rd term

3p - 1= (p-1) + (3-1)4

3p - p = 2*4

2p = 8

p = 4

Value of p = 4

Answer 2

answer::-

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