Question

If p-1, p+3, 3p-1, are in AP
then p=?​

Answer 1

Answer:4

Step-by-step explanation:

IN AP,

(P+3)-(P-1)=(3P-1)-(P+3)

4=2P-4

8=2P

P=4

Answer 2

Answer:

• in AP
• $\\ b - a = c - a \\ p + 3 - p + 1 = 3p - 1 - p - 3 \\ 4= 2p - 4 \\ 4 + 4 = 2p \\ 2p = 8\\ p = 4$