If p-1, p+3, 3p-1aes in AP, the p is equal to
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Step-by-step explanation:
we kown that the formula
d= a2-a1
given :-
a1=p-1 , a2= p+3 and a3= 3p-1
a +d = p-1 ...(1) or a+ 2d= p+3....(2)
By elmination method
a + d = p - 1
a + 2d=p + 3
- - -
-d = p - 1 -(p + 3)
= p- 1 - p - 3
-d = - 4
d = 4
Now put equation 1
a + d = p- 1
a + 4 = p- 1
a = p- 1- 4
=p -5
a1= p -1
p - 5= p - 1
p- p = -1 + 6
0 = 5
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