Question

If p+1/p =5 then find (p-1/p)^2

Answer 1

there you go.hope it helps...

Answer 2

Answer:

The value of $(p-\frac{1}{p} )^{2}$ = 21.  

Step-by-step explanation:

Given that p + 1/p = 5

We have to find value of (p - 1/p)² value

(a + b)² = a² +2ab +b²

(a - b)² = a² -2ab +b²

$(p + \frac{1}{p} )^{2} = p^{2} +(\frac{1}{p} )^{2} +2p(\frac{1}{p} )$ = (5)² = 25

$p^{2} +(\frac{1}{p})^{2} +2 =25$

$p^{2} +(\frac{1}{p})^{2} =25-2=23$

(p - 1/p)² value is

$(p-\frac{1}{p})^{2} = p^{2} +(\frac{1}{p} )^{2} -2(p)(\frac{1}{p} )$ = $p^{2} +(\frac{1}{p} )^{2} -2$ = 23 - 2 = 21.

Therefore, $(p-\frac{1}{p} )^{2}$ = 21.