Question

If p=2-√3,q=√3-√7 and r=√7-√4 then find the value of p cube +q cube + r cubes

Answer 1

Given

If p=2-root(3),q=√3-√7 and r=√7-√4

required

find the value of p cube +q cube + r cubes

p=2-root(3)

root(3)=1.732

p=0.267

a=p^3=(0.267)^3

a=0.019

q=root(3)-root(7)

root(3)=1.732

root(7)=2.645

q=1.732-2.645

q=-0.913

b=q^3=(-0.913)^3

b=-0.761

r=root(7)-root(4)

root(7)=2.645

root(4)=2

r=2.645-2

r=0.645

c=r^3=(0.645)^3

c=0.268

x=p^3+q^3+r^3

x=0.268-0.761+0.019

x=-0.474