Question

If P =(2,5),Q=(x-7) and PQ =13what is the value of x

Answer 1

Step-by-step explanation:

Click here to get an answer to your question ✍️ if p=(2,5)q=(x, -7) then find possible values of x pq =13.

62 votes

13^2=(x-2)^2+(-7-5)^2=169=(x-2)^2+144=25=(x-2)^2=x-2=+5 or -5x=7 or -3pls mark as brainliest. More

2 votes

p = 2,3 q = X,-7 A/q PQ =13PQ^2= 13^2(x - 2)² + (-7- 5)² = 169⇒ (x - 2)^2 = 169-144= 25