Question

The cost of 6 chairs and 4 tables be ₹ 8050 and the cost of 4 chairs and 2 tables be ₹ 4800 . The cost of each chair and table will be :
Options are :
i) ₹ 700 and ₹ 890
ii) ₹ 775 and ₹ 850
iii) ₹ 720 and ₹ 870
iv) None of these
Full explanation with step by step solutions .​

Answer 1

Answer:

The cost of one chair is 775 rupees and the cost of one table is 850 rupees

Step-by-step explanation:

Let the cost of the chair be x and the cost of the table be  y.

It is given that cost of 6 chairs and 4 tables is 8050. This corresponds to the equation,

$6x+4y=8050$

Also, the cost of 4 chairs and 2 tables is 4800.The equivalent equation is,

$4x+2y=4800$

Now we can solve these equations simultaneously.

Multiply the second equation by 2, we get,

$8x+4y=9600$

Now subtract the first equation from the third one, we get

$8x+4y-(6x+4y)=9600-8050\\\\2x= 1550\\\\x=\dfrac{1550}{2}=775$

Substituting the value of x in the second equation, we obtain,

$4\times 775+2y=4800\\\\3100+2y=4800\\\\2y=4800-3100 =1700\\\\y= \dfrac{1700}{2}=850$

So the cost of one chair is 775 rupees and the cost of one table is 850 rupees. Hence option (iii) is the correct one.

Answer 2

QUESTION :

• The cost of 6 chairs and 4 tables be ₹ 8050 and the cost of 4 chairs and 2 tables be ₹ 4800 . The cost of each chair and table will be :

GIVEN :

• cost of 6 chairs and 4 tables be ₹ 8050

• cost of 4 chairs and 2 tables be ₹ 4800

TO FIND :

• The cost of each chair and table will be = ?

SOLUTION :

cost of one chair will be = a

cost of one table will be = b

• cost of 6 chairs and 4 tables be = ₹ 8050

• cost of 4 chairs and 2 tables be = ₹ 4800

then, we will add 8 + 6 and write 9600

then, we will minus 9600 - 8050 we get :

• 9600 - 8050 = 1550

• = 1550

a = 1550/2 = 775

then, we will putting the value of a :

• = 4800

then, we will minus 4800 with 3100 we get :

• 4800 - 3100 = 1700

b = 1700/2 = 850