if P^2=7+4√3 than P=?
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Concept
The formula a^2 - b^2 is also known as the "difference of squares formula". The square of a minus the square of b is used to find the difference between two squares without actually calculating the squares.
It is one of the algebraic identities.
It is used to factor binomial squares.
a^2 - b^2 = (a - b) (a + b)
Multiplying (a - b) and (a + b) gives us
=a(a+b) -b(a + b)
=a^2 + ab - ba - b^2
=a^2 + 0 + b^2
=a^2 - b^2
Therefore verified
a^2 - b^2 = (a - b) (a + b)
Given
It is given that P^2=7+4√3
Find
We need to find the value of P
Solution
P^2=7+4√3
P^2 = (√(7+4√3))^2
P^2 - (√(7+4√3))^2 = 0
(P - √(7+4√3)) (P + √(7+4√3)) =0
P = ± √(7+4√3 )
Hence the value of P is ± √(7+4√3 )
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