Question

if p=2-a,prove that a³+6ap+p³-8=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Given p=2−a

to prove a

3

+6ap+p

3

−8=0...(1)

Now put the value of P in eq (1)

a

3

+6a(2−a)+(2−a)

3

−8=0

⇒a

3

+12a−6a

2

+8−a

3

−12a+6a

2

−8=0

[∴(a−b)

3

=a

3

−b

3

−3a

2

b+3ab

2

]

⇒0=0 (By eliminating equal terms we

have LHS = RHS)

R