Math, asked by snehal1566, 1 year ago

If p=-2,q=-1,r=3 then p^2+q^2-r^2

Answers

Answered by Anonymous
2

Answer:

Given,

p = -2

q = -1

r = 3

Step-by-step explanation:

= (-2)^3 + (-1)^3 + (3)^3 + 3 x -1 x -2 x 3

= -8 + (-1) + 27 + 9 x 2

= -8 - 1 + 27 + 18

= 27 + 18 - 8 - 1

= 45 - 9

= 36

Answered by KINGSHRIJEET
0
THE ANSWER FOR THIS QUESTIONS IS :
AS WE KNOW THAT P= -2, Q= -1 ,R= 3
THEREFORE P^2+Q^2-R^2

= (-2)^2 + (-1)^2 - 3^2
= 4+1-9
=5-9
=4
Similar questions