If p=-2,q=-1,r=3 then p^2+q^2-r^2
Answers
Answered by
2
Answer:
Given,
p = -2
q = -1
r = 3
Step-by-step explanation:
= (-2)^3 + (-1)^3 + (3)^3 + 3 x -1 x -2 x 3
= -8 + (-1) + 27 + 9 x 2
= -8 - 1 + 27 + 18
= 27 + 18 - 8 - 1
= 45 - 9
= 36
Answered by
0
THE ANSWER FOR THIS QUESTIONS IS :
AS WE KNOW THAT P= -2, Q= -1 ,R= 3
THEREFORE P^2+Q^2-R^2
= (-2)^2 + (-1)^2 - 3^2
= 4+1-9
=5-9
=4
AS WE KNOW THAT P= -2, Q= -1 ,R= 3
THEREFORE P^2+Q^2-R^2
= (-2)^2 + (-1)^2 - 3^2
= 4+1-9
=5-9
=4
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