Question

If p=-2,q=-1,r=3 then p3+q3+r3+3pqr=?

Answer 1

hope this will help you.

Answer 2

Given,
p = -2
q = -1
r = 3

So,
p^3 + q^3 + r^3 + 3pqr
= (-2)^3 + (-1)^3 + (3)^3 + 3 x -1 x -2 x 3
= -8 + (-1) + 27 + 9 x 2
= -8 - 1 + 27 + 18
= 27 + 18 - 8 - 1
= 45 - 9
= 36