Question

if p/2=q/3=r/5, then what is value of {(2p+2q+2r)/4r}

Answer 1

Answer:

2

Step-by-step explanation:

let p/2=q/3=r/5=a

then, p =2a

q =3a

r =5a

put in equation...

then, {(4a+6a+10a)/10a} = {(4+6+10)/10} = 10/5=2

Answer 2

The value of {(2p+2q+2r)/4r} = 1

Given,

p/2=q/3=r/5

Now consider,

p/2=r/5

p = 2r/5 ........(1)

q/3=r/5

q = 3r/5 ...........(2)

Now, we have,

{(2p+2q+2r)/4r}

using the values of equations (1) and (2) in the above equation, we get,

{(2(2r/5)+2(3r/5)+2r)/4r}

= {(4r/5 + 6r/5 + 2r) / 4r}

= {( (4r+6r+10r)/5 ) / 4r}

= 20r / (5×4r)

= 20r / 20r

= 1