Question

The work done by a call in 10s to send 50C of charge through resistor of resistance 2ohm is?

Answer 1

Answer:

Explanation:

By ohm's law

V=IR

I=q/t

=50c/10s

I=5A

Now,

V=IR,

=5×2

V=10v

Work done = V×C

10×50

Therfore, work done =500 joules

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