Question

If p = 2x2 - 5x + 2, q = 5x2 + 6x - 3, r = 3x2 - x - 1, find the value of 2p - q + 3r

Answer 1

Answer:

2p-q+3r=8x^2-19x+4

Step-by-step explanation:

given

p=2x^2-5x+2

q=5x^2+6x-3

r=3x^2-x-1

find 2p-q+3r

=2(2x^2-5x+2)-(5x^2+6x-3)+3(3x^2-x-1)

=(4x^2-10x-4)-(5x^2+6x-3)+(9x^2-3x-3)

=4x^2-10x-4-5x^2-6x+3+9x^2-3x-3

=8x^2-19x+4

Answer 2

Given:

The given expressions are

$p = 2 {x}^{2} - 5x + 2 \\ q = 5 {x}^{2} + 6x - 3 \\ r = 3 {x}^{2} - x - 1$

To find:

The value of 2p-q+3r.

Solution:

To determine the value of 2p-q+3r we have to follow the below steps as follows-

The given three expressions of p, q and r are as follows-

$p = 2 {x}^{2} - 5x + 2 \\ q = 5 {x}^{2} + 6x - 3 \\ r = 3 {x}^{2} - x - 1$

To determine the value of 2p-q+3r we have to multiple 2 with p and 3 with r.

Hence we can write-

$2( 2 {x}^{2} - 5x + 2 ) - ( 5 {x}^{2} + 6x - 3) + 3( 3 {x}^{2} - x - 1) \\ 4 {x}^{2} - 10x + 4 - 5 {x}^{2} - 6x + 3 + 9 {x}^{2} - 3x - 3 \\ 8 {x}^{2} - 19x + 4$

The value of 2p-q+3r is

$8 {x}^{2} - 19x + 4$