Question

if p=4, q= -3 and r=2, find the value of : p³+q³-r³-3pqr
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Answer 1

Answer:

Here is your answer mate,

Step-by-step explanation:

QUESTION,

if p=4, q= -3 and r=2, find the value of : p³+q³-r³-3pqr

Answer,

Given,

P=4, q =-3 and r =2

Substituting these values in given polynomial

p³+q³-r³-3pqr,

${4}^{3} + ( { - 3})^{3} - ( {2}^{3} ) - ({3 \times 4 \times ( - 3) \times 2})$

$64 - 27 - 8 - ( - 72)$

$64 - 27 - 8 + 72$

$37 - 8+ 72$

$37 + 64$

$101$

Have a good day ❤️

Answer 2

Solution :-

→ p³ + q³ - r³ - 3pqr

putting p = 4, q = -3 and r = 2 we get,

→ (4)³ + (-3)³ - (2)³ - 3 * 4 * (-3) * 2

→ 64 + (-27) - 8 + 72

→ 64 + 72 - (27 + 8)

→ 136 - 35

→ 101 (Ans.)

Hence, required value is equal to 101 .

Learn more :-

*यदि (5, z) 4x - 3y = 11 का हल है, तो z का मान ज्ञात कीजिए।* 1️⃣ 5 2️⃣ 19/3 3️⃣ 31/3 4️⃣ 3

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