Question

If p=4, q=3 and r=2, then find the value of the algebraic expression p²+q²+r²/pq+qr-pr



need step by step solving​

Answer 1

[tex]p = 4\\ q = 3\\ r = 2\\ \\ \frac{p^2 + q^2 - r^2}{pq + qr - pr}\\\\ = \frac{4^2 + 3^2 - 2^2}{(4)(3) + (3)(2) - (4)(2)}\\ \\ = \frac{16 + 9 -4}{12 + 6 - 8 }\\\\ = \frac{25-4}{18-8}\\ \\ = \frac{21}{10}\\ = 2.1[/tex]

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