Question

If P=4i - 2j+6k and Q = i-2j-3k. then the angle
which P +Q
makes with x-axis is​

Answer 1

Answer:

the sum of A and B is C ( assumption) = 5i-4j+3k. the direction cosines are, 5/(5^2+4^2+3^2)^(1/2)=5/5√2,(—4/5√2),3/5√2. Now let us assume ( yeah we r assuming much.) that the angle is ¢(haven't found any other sign) . So d.cs of x axis are 1,0,0. So cos¢= 5/5√2. So cos¢ = 1/√2. So ¢=. π/4. Hope it will help. Best of luck

Answer 2

........here is the answer.....

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