Question

if p=5+2root06 and x=1÷p then what will be the value of p squar +px square r

Answer 1

(5+√2)^2+(p*1/p) ^2r
25+2+10√2+1+r
28+10√2+r

Answer 2

$<h2><marquee behavior="alternate"><font color="Blue"><u>Hello</font> <font color="lime"><u>Friend</marquee></font></u></h2>$

$If \: p = 5 + 2\sqrt{6}....(1) \: \\ and \\ x = \frac{1}{p} \\ = > px = 1....(2) \\ so,\: \: {p}^{2} + px = 25+4(6) + 1(from \: 1 \: and \: 2) \\ = 50$

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