Question

IF P=9;then find the degree of polynomial f[x]=[x-p]3+729
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Answer 1

If p=  9 in f(x) = [x - p]3 = 729  then , f(x) = [x - 9]3 + 729 => 3x - 27 + 729 => 3x - 3^3 + 3^6. the greatest power is 6 in the polynomial. therefore 6 is the degree of the polynomial.

Answer 2

Answer:

Here degree of this polynomial is 3

since The degree of a polynomial is the highest power of x with non zero coefficient.

f(x)=(x-p)3+729

= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}

=x^3-729-(3*x*9(x-9)) {since given p=9

=x^3-729-27x^2+243x

Rearranging we will get

p(x)=x^3 - 27x^2 +243x -729

Highest ie,degree highest power of x (with nonzero coefficient)is 3.So degree of this polynomial is 3

Step-by-step explanation:

Here degree of this polynomial is 3

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}=x^3-729-(3*x*9(x-9)) {since given p=9

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}=x^3-729-(3*x*9(x-9)) {since given p=9=x^3-729-27x^2+243x

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}=x^3-729-(3*x*9(x-9)) {since given p=9=x^3-729-27x^2+243xRearranging we will get

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}=x^3-729-(3*x*9(x-9)) {since given p=9=x^3-729-27x^2+243xRearranging we will getp(x)=x^3 - 27x^2 +243x -729

Here degree of this polynomial is 3since The degree of a polynomial is the highest power of x with non zero coefficient.f(x)=(x-p)3+729= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}=x^3-729-(3*x*9(x-9)) {since given p=9=x^3-729-27x^2+243xRearranging we will getp(x)=x^3 - 27x^2 +243x -729Highest ie,degree highest power of x (with nonzero coefficient)is 3.So degree of this polynomial is 3

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