Question

if p =9 then find the degree of the polynomial f (x) is equal to (x-p)^2 +729 ?​

Answer 1

Answer:

Here degree of this polynomial is 3

since The degree of a polynomial is the highest power of x with non zero coefficient.

f(x)=(x-p)3+729

= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}

=x^3-729-(3*x*9(x-9)) {since given p=9

=x^3-729-27x^2+243x

Rearranging we will get

p(x)=x^3 - 27x^2 +243x -729

Highest ie,degree highest power of x (with nonzero coefficient)is 3.So degree of this polynomial is 3

Answer 2

Answer:

Step-by-step explanation:

Here degree of this polynomial is 3

since The degree of a polynomial is the highest power of x with non zero coefficient.

f(x)=(x-p)3+729

= x^3-p^3-(3*x*p(x-p)) +729 {since (a − b)3 = a3 − b3 − 3ab(a − b)}

=x^3-729-(3*x*9(x-9)) {since given p=9

=x^3-729-27x^2+243x

Rearranging we will get

p(x)=x^3 - 27x^2 +243x -729

Highest ie,degree highest power of x (with nonzero coefficient)is 3.So degree of this polynomial is 3