Question

if p=999,then find the value of (p(p^2 +3p+1))1/3

Answer 1

☆☆YOUR ANSWER IS HERE☆☆

SOLUTION:--


Science

We have,                 y= [p(p2+3p+1)]13    
 putting p=999 in above polynomialy=
 
[999 (9992+3(999)+1]13

=[999(998001+2997+1)]13

=[999×1000999]13

=999−−−√3×1000999−−−−−−−

√3=9.996×100.03=999.89 Answer