Question

if P(A)=1/2,P(B)=0,thenP(A/B) is​

Answer 1

This is not possible,, your qn is wrong

Because sum of all the probabilities is always 1 but here it is (1/2)

Answer 2

P(A/B) is not defined.

Step-by-step explanation:

Given : If $P(A)=\frac{1}{2}$ ,P(B)=0.

To find : The value of $P(A/B)$ ?

Solution :

We have given,

P(B)=0

i.e. $B=\phi$ a empty set

So, $A\cap B=\phi$

The probability of intersection is $P(A\cap B)=0$

Now we know that,

$P(A/B)=\frac{P(A\cap B)}{P(B)}$

$P(A/B)=\frac{0}{0}$

Therefore, P(A/B) is not defined.

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