Math, asked by daris52, 6 hours ago

If p(A)=x/3 and p(Ā)=2/5, then find x​

Answers

Answered by hukam0685
6

Step-by-step explanation:

Given:p(A)=x/3 and p(Ā)=2/5

To find: Value of x

Solution:

Tip: Probability of happening of an event 'p(A)' and not happening of the same event 'p(Ā)' add to one.

i.e.

P(A)+P(Ā)=1

Step 1: Add both probabilities and equate to 1

 \frac{x}{3}  +  \frac{2}{5}  = 1 \\

Step 2: Take 2/5 to RHS and solve

 \frac{x}{3}  = 1 -  \frac{2}{5}  \\  \\  \frac{x}{3}  =  \frac{5 - 2}{5}  \\  \\  \frac{x}{3}  =  \frac{3}{5}  \\  \\

Step 3: Cross multiply 3 to other side

x =  \frac{3 \times 3}{5}  \\  \\ x =  \frac{9}{5}  \\

Final answer:

\bold{\red{x =  \frac{9}{5}}}  \\

Verification:

P(A)+P(Ā)=1

Put value of x in LHS

  = \frac{ \frac{9}{5} }{3}  +  \frac{2}{5}  \\  \\  =  \frac{9}{15}  +  \frac{2}{5}  \\  \\  =  \frac{9 + 2 \times 3}{15}  \\  \\  =  \frac{9 + 6}{15}  \\  \\  =  \frac{15}{15}  \\  \\  = 1 \\  \\  = RHS \\  \\

Hence Proved.

Hope it helps you.

To learn more on brainly:

1) find the the value of x if 3^2x+1=243

https://brainly.in/question/38428028

Answered by Missincridedible
6

Answer:

Step-by-step explanation:

Given:p(A)=x/3 and p(Ā)=2/5

To find: Value of x

Solution:

Tip: Probability of happening of an event 'p(A)' and not happening of the same event 'p(Ā)' add to one.

i.e.

P(A)+P(Ā)=1

Step 1: Add both probabilities and equate to 1

 \frac{x}{3}  +  \frac{2}{5} = 1

Step 2: Take 2/5 to RHS and solve

 \frac{x}{3} = 1 -  \frac{2}{5} \\  \frac{x}{3} =  \frac{5 - 2}{5}  \\ \frac{x}{3} =  \frac{3}{5}

Step 3: Cross multiply 3 to other side

x =  \frac{3×3}{5}  \\ x =  \frac{9}{5}

Final answer:

x =  \frac{9}{5}

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