Question

If P=a⁴+ a³+ a² - 6,
Q = a² - 2a³- 2 + 3a
and R=8-3a-2a²+a³,
then the value of P + Q + R is
(a) a⁴
(b) a³
(c) 2a⁴
(d) 3a⁴​

Answer 1

$P=a⁴+ a³+ a² - 6 \\ Q = a² - 2a³- 2 + 3a \\R=8-3a-2a²+a³ \\ \\ \implies a⁴+ \cancel {a³}+ \cancel{a²} - \cancel{6 }+\cancel{a²} - \cancel{2a³}- \cancel2 + 3a +\cancel 8-3a-\cancel{2a²}+\cancel{a³} \\ \implies {a}^{4} + 3 - 3a \\ \huge \boxed{ {a}^{4} }$

Answer 2

Step-by-step explanation:

$P=a⁴+ a³+ a² - 6 \\ Q = a² - 2a³- 2 + 3a \\R=8-3a-2a²+a³ \\ \\ \implies a⁴+ \cancel {a³}+ \cancel{a²} - \cancel{6 }+\cancel{a²} - \cancel{2a³}- \cancel2 + 3a +\cancel 8-3a-\cancel{2a²}+\cancel{a³} \\ \implies {a}^{4} + 3 - 3a \\ \huge \boxed{ {a}^{4} }$