Question

if p and q are the solution of the equation 2x square +10x + 7=0 where p>q . find the value of p-q​

Answer 1

Answer:

Let p and q are roots of the following equation:

$2x^{2} +10x +7 =0$

where p>q

=($-10$±$\sqrt{100-4*2*7 }$)/4

=(-10±$\sqrt{44}$)/4

p=(-5+√11)/2  and q=(-5-√11)/2

p-q = $\frac{(-5+\sqrt{11} )}{2}$ - $\frac{(-5-\sqrt{11} )}{2}$

p-q = $\frac{-5+\sqrt{11}+5+\sqrt{11} }{2}$

p-q = $\sqrt{11}$ , which is approx. 3.315

Answer 2

HERE IS YOUR SOLUTION...

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