Question

If p and q are the two digits of the number 653pq such that this number is divisible by 80, then p+q is equal to :The difference between the squares of two consecutive odd integers is always divisible by

Answer 1

Answer:

6

Step-by-step explanation:

65360 is divisible by 80. So p=6, q=0. And if we take 7 and 5 as the two consecutive odd integers, 7^2-5^2=24, which is divisible by 6.