Math, asked by syedajuweriya, 9 months ago

A wires in the form of a square of side 49.5 CM its straighted and bent into a semicircle what is the radius of the semicircle so formed???

Answers

Answered by madmaxYT

1

Answer:

r= 7.875 cm

Step-by-step explanation:

length of wire= circumference

therefore

circumference=2πr

495/10=2 × 22/7 × r

495÷5/ 10÷5 = 2× 22/7 × r

99/2 = 2× 22/7 × r

99÷11/2 =2× 22÷11/7 ×r

9/2 = 2× 2/7 ×r

by cross multiplication

r= 63/8

r = 7.875vcm approx**

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