A wires in the form of a square of side 49.5 CM its straighted and bent into a semicircle what is the radius of the semicircle so formed???
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Answer:
r= 7.875 cm
Step-by-step explanation:
length of wire= circumference
therefore
circumference=2πr
495/10=2 × 22/7 × r
495÷5/ 10÷5 = 2× 22/7 × r
99/2 = 2× 22/7 × r
99÷11/2 =2× 22÷11/7 ×r
9/2 = 2× 2/7 ×r
by cross multiplication
r= 63/8
r = 7.875vcm approx**
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