if p and q are the zero of quadratic polynomial x^2+mx +n^2+ a then value of p^2 +q^2+pq is
Answers
Answer:
Step-by-step explanation:
0
Answer:
m² - n² - a
Note:
★ The possible values of the variable for which the polynomial becomes zero are called its zeros.
★ To find the zeros of the polynomial p(x) , operate on p(x) = 0 .
★ A quadratic polynomial can have atmost two zeros .
★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;
• Sum of zeros , (α + ß) = -b/a
• Product of zeros , (αß) = c/a
★ If α and ß are the zeros of any quadratic polynomial , then it is given by ;
x² - (α + ß)x + αß
★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then they (α and ß) are also the zeros of the quadratic polynomial k(ax² + bx + c) , k≠0.
Solution:
Hence,
The given quadratic polynomial is ;
x² + mx + (n² + a)
Also,
It is given by that p and q are the zeros of the given quadratic polynomial .
Thus,
Sum of zeros will be ;
p + q = -m/1 = -m
Also,
Product of zeros will be ;
pq = (n² + a) / 1 = n² + a
Now,
p² + q² + pq = p² + q² + 2pq - pq
= (p² + q² + 2pq) - pq
= (p + q)² - pq
= (-m)² - (n² + a)
= m² - n² - a
Hence,
The required answer is :
m² - n² - a