Question

If p and q are the zeroes of p(x) = kx2 – 3x + 2k and p+q=pq then find the value of k.

Answer 1

Hi...☺

Here is your answer...✌

p(x) = kx² - 3x + 2k

a = k , b = -3 , c = 2k

Given that,

p and q are zeros of p(x)

and

p + q = pq

=> -b/a = c/a

[ sum of zeros = p+q = -b/a
product of zeros = pq = c/a ]

=> -b = c

['a' get cancelled in denominator]

=> -(-3) = 2k

=> 3 = 2k

=> k = 3/2

Answer 2

p(x)= 2kx-3x+2k=0

p+q= -b/a = -(-3)/2k

pq= 2k/2k = 1

p+q = pq (given)

3/2k = 1

2k = 3

k = 3/2 Ans