if p and q are the zeroes of polynomial f(x)= 2x^2 -7x +3, find the value of p^2 + q^2.
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Answered by
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Given polynomial f(x)=2x²-7x+3
and p,q are two zeroes of f(x).
Compare f(x) with ax²+bx+c
we get,
a=2, b=-7,c=3
Now,
i ) p+q = -b/a = -(-7)/2=7/2
ii ) pq = c/a = 3/2
iii) p²+q² = (p+q)²-2pq
=(7/2)²-2×3/2
=(49/4)-3
= (49-12)/4
= 37/4
Therefore,
p²+q²= 37/4
••••
Answered by
3
Answer:
Psq+qsq=37÷4
Step-by-step explanation:
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ChirayuC:
thank u dude
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