if p and q are the zeroes of the quadratic polynomial x^2 -5x +4 .Find the value of p^2 q+ q^2 +p
Answers
Answered by
10
if p and q are roots of
=> x²-5x+4 = 0
=> (x-4)(x-1) = 0
then
p+q = 5
and
pq = 4
for
=> p²q + q²p
= pq(p+q)
= 4×5
= 20
hope it helps you
@di
=> x²-5x+4 = 0
=> (x-4)(x-1) = 0
then
p+q = 5
and
pq = 4
for
=> p²q + q²p
= pq(p+q)
= 4×5
= 20
hope it helps you
@di
Adityaadidangi:
p²q+q²p is the question
p square q +q square p is the question
is the answer correct
answer is correct
what if p and q are the roots
then what will be the answer
roots and zeroes are used for same
bro plz tell me last time
is the answer correct
yes
Answered by
5
Answer:
Step-by-step explanation:
In the quadratic polynomial x^2-5x+4which is in the form of ax^2+bx+c.,
a=5 , b=(-5), c=4
p & q are zeros
:. p+q=c÷a=4÷1=4
P×q= -b÷a=-(-5)÷1=5
We have,
p^2q+q^2p
=pq(p+q)
=5(4)
=20
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