If p and q are the zeroes of the quadratic polynomial x²+mx+n²+a find p²+q²+pq.
a. 0
b. a
c. -a
d. m or -m
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Sum of zeroes/roots p+q=-m____(1)
Product of zeroes p*q=n^2____(2)
Squaring equation (1) on both sides,
p^2 + q^2 + 2pq = m^2_____(3)
Substituting value of p*q from equation (2) in (3)
p^2 + q^2 + 2n^2 =m^2
Therefore, p^2 + q^2 =m^2 - 2n^2
So value of p^2 + q^2 +pq
=m^2 - 2n^2 +n^2 (since pq=n^2 from (2) )
=m^2 - n^2 or
=(m+n)(m-n)
And you can also solve this as shown in picture
hope this will help you....
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