If p and q are zeroesof polynomial x2_2x-8 then find thevalue of p2+ q2
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Answered by
1
p^2+q^2 = (p+q)^2-2pq
= (-b/a)^2 - 2(c/a)
= (2/1)^2 - 2(-8)
= 4 + 16 = 20 ;)
= (-b/a)^2 - 2(c/a)
= (2/1)^2 - 2(-8)
= 4 + 16 = 20 ;)
Answered by
1
finally the answer is 20
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