Question

If p and q are zeros of the polynomial 4x^2 +3x+7 then 1/p+1/q is equal to

Answer 1

EXPLANATION.

• GIVEN

p and q are the zeroes of the polynomial

4x^2 + 3x + 7

TO FIND 1/P + 1/Q

Let,

sum of zeroes of the polynomial =

p + q = -b/a = -3/4

products of zeroes of polynomial =

pq = c/a = 7/4

according to the question,

Find 1/p + 1/q

1/p + 1/q = q + p / pq

-3/4/7/4 =

-3 / 7 = answer

More information,

Formula of quadratic polynomial

sum of zeroes of polynomial = a + b = -b/a

products of zeroes of polynomial = ab = c/a

$\bigstar\orange{\boxed{{x}^{2} - ( \alpha + \beta )x + \alpha \beta}}$

formula of cubic polynomial,

sum of zeroes = a + b + c = -b / a

sum of products of zeroes at two times =

ab + bc + ca = c / a

products of zeroes of polynomial =

ABC = -d / a

$\bigstar\green{\boxed{{x}^{3} - ( \alpha + \beta + \gamma ) {x}^{2} + ( \alpha \beta + \beta \gamma + \gamma \alpha )x - \alpha \beta \gamma}}$